At $273 K$ the second virial coefficient of a gas is $B = - 21.5 mL mo l^{- 1}$ . The pressure-series coefficient $B^{'} = B / RT$ , in units of $1 0^{- 4} at m^{- 1}$ (one decimal, $R = 0.0821 L atm K^{- 1} mo l^{- 1}$ ), is

Numerical answer type, answer in 1e-4 atm^-1, tolerance 0.2.

Answer: -9.6 1e-4 atm^-1

B^{'} = \frac{B}{RT} = \frac{- 0.0215}{0.0821 \times 273} = \frac{- 0.0215}{22.413} = - 9.5925 e - 04 at m^{- 1}

, i.e.

- 9.6 \times 1 0^{- 4} at m^{- 1}