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JEE Main levelSingle correct optionDifficulty 2 of 3rg139

Two gases have the same van der Waals constant $a$ but gas M has $b$ twice that of gas N. The ratio of their Boyle temperatures $T_{B} (M) / T_{B} (N)$ is

A $2$
B $1/2$
C $4$
D $1$

Answer: B

T_{B} = a / R b

is inversely proportional to

b

. Doubling

b

halves

T_{B}

, so the ratio is

1/2

.

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