JEE Advanced levelSingle correct optionDifficulty 3 of 3rg076
The van der Waals constants of a gas are a=6.49L2atmmol−2 and b=0.0562Lmol−1. If 1mol of this gas at 400K occupies 0.800L, the ratio PvdW/Pideal is closest to (R=0.0821LatmK−1mol−1)
A0.83
B0.93
C1.00
D1.08
Answer: A
Pideal=32.84/0.800=41.05atm. PvdW=0.743832.84−0.6406.49=44.15−10.14=34.01atm. Ratio =0.829≈0.83. The large a (sulfur dioxide-like) makes attraction dominate.