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Deviation from ideal behaviour and compressibility factor
JEE Main level
Single correct option
Difficulty 2 of 3
rg059
At
300
K
and
60
atm
,
1
mol
of a gas occupies
0.328
L
. Taking
R
=
0.0821
L
atm
K
−
1
mo
l
−
1
, the compressibility factor is closest to
A
0.60
B
0.80
C
1.00
D
1.25
Answer: B
Z
=
n
RT
P
V
=
1
×
0.0821
×
300
60
×
0.328
=
24.63
19.68
=
0.799
, so
Z
≈
0.80
. The gas is more compressible than an ideal gas at this state.
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