Using the same methane constants ( $a = 2.25 L^{2} atm mo l^{- 2}$ , $b = 0.0428 L mo l^{- 1}$ ), the critical pressure in atm (one decimal) is

Numerical answer type, answer in atm, tolerance 0.3.

Answer: 45.5 atm

P_{c} = \frac{a}{27 b ^{2}} = \frac{2.25}{27 \times ( 0.0428 ) ^{2}} = \frac{2.25}{0.049460} = 45.49 atm

, i.e.

45.5 atm