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JEE Advanced levelSingle correct optionDifficulty 3 of 3rg032

A gas has $a = 0.034 L^{2} atm mo l^{- 2}$ and $b = 0.0237 L mo l^{- 1}$ . Which statement about its behaviour at $298 K$ is correct? ( $R = 0.0821 L atm K^{- 1} mo l^{- 1}$ )

AIt is below its Boyle temperature, so $Z$ first decreases with pressure
BIt is above its inversion temperature, so it warms on Joule-Thomson expansion
CIt is below its inversion temperature, so it cools on Joule-Thomson expansion
DIt is at its Boyle temperature

Answer: B

T_{B} = a / R b = 0.034/ (0.0821 \times 0.0237) = 17.5 K

and

T_{i} = 2 T_{B} = 34.9 K

. Room temperature (

298 K

) is far above both, so the gas (helium-like) has

Z

greater than 1 at all pressures and warms on throttling. Only option B is correct.

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