JEE Advanced levelOne or more correct optionsDifficulty 3 of 3qa184
Which of the following correctly describe the behaviour of HX2S gas liberated from sulphide with dilute acid?
AIt blackens paper moistened with lead acetate because PbS forms
BIt turns acidified KX2CrX2OX7 paper green with deposition of sulphur
CIt gives a black precipitate with aqueous CuSOX4
DIt gives a white milky precipitate of CaS with lime water
Answer: A, B, C
HX2S+Pb(CHX3COO)X2PbS+2CHX3COOH and CuS are both black. CrX2OX7X2−+3HX2S+8HX+2CrX3++3S+7HX2O gives green CrX3+ and sulphur. Lime water simply absorbs HX2S to give soluble Ca(HS)X2/CaS (hydrolysed), not a milky precipitate.