Match the species (List I) with the description (List II). List I: P $[Fe (H X_{2} O) X_{5} NO] X^{2 +}$ , Q $CrO X_{2} Cl X_{2}$ , R $Fe X_{4} [Fe (CN) X_{6}] X_{3}$ , S $Na X_{4} [Fe (CN) X_{5} NOS]$ . List II: 1 dark blue, contains Fe(III) and Fe(II); 2 brown, Fe formally +1 with $NO X^{+}$ ; 3 orange-red volatile liquid, Cr(VI); 4 purple-violet, formed from nitroprusside and $S X^{2 -}$ .

AP-2, Q-3, R-1, S-4
BP-2, Q-3, R-4, S-1
CP-3, Q-2, R-1, S-4
DP-1, Q-3, R-2, S-4

Answer: A

The brown ring complex is brown with Fe(+1) and

NO X^{+}

. Chromyl chloride is an orange-red volatile liquid with Cr(VI). Prussian blue contains 4 Fe(III) and 3 Fe(II) (12 = 3 x 4 charge balance). The nitroprusside sulphide product is purple-violet. The matching is P-2, Q-3, R-1, S-4.

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Answer: A

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