JEE Advanced levelSingle correct optionDifficulty 3 of 3qa145
1.34g of anhydrous NaX2CX2OX4 (Na 23, C 12, O 16) is warmed with excess concentrated HX2SOX4. The gas mixture is passed through excess concentrated KOH solution and the leftover dry gas is collected at STP (molar volume 22.4L/mol). Its volume is:
A112mL
B336mL
C448mL
D224mL
Answer: D
NaX2CX2OX4+HX2SOX4NaX2SOX4+CO+COX2+HX2O. Molar mass of sodium oxalate = 134, so n=1.34/134=0.0100mol. KOH removes COX2, leaving 0.0100mol CO, i.e. 0.0100×22400=224mL.