JEE Main levelSingle correct optionDifficulty 2 of 3qa100
Which of the following arranges the silver halides in decreasing order of solubility in aqueous ammonia (of the same concentration)?
AAgBr>AgCl>AgI
BAgI>AgBr>AgCl
CAgCl>AgI>AgBr
DAgCl>AgBr>AgI
Answer: D
Solubility in NHX3 through [Ag(NHX3)X2]X+ formation depends on the solubility product: AgCl (largest Ksp) dissolves in dilute NHX3, AgBr only partly in concentrated NHX3, and AgI (smallest Ksp) not at all.