JEE Advanced levelSingle correct optionDifficulty 3 of 3qa088
In the nitrate ring test, the brown species [Fe(HX2O)X5NO]X2+ is best described by treating NO as the nitrosonium ligand NOX+. Assuming the complex is high spin, the oxidation state of iron and the spin-only magnetic moment (BM) are respectively
A+1 and 3.87
B+2 and 4.90
C+1 and 1.73
D+3 and 5.92
Answer: A
Charge balance: x+0+1=+2 gives x=+1. Fe(I) is d7; in the high-spin arrangement there are three unpaired electrons, so μ=3×5=15=3.87 BM. This is consistent with the observed paramagnetism of the brown ring complex.