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NEET levelSingle correct optionDifficulty 1 of 3qa076

The brown ring formed at the junction of the two layers in the nitrate ring test is due to the complex

A $[Fe (H X_{2} O) X_{6}] X^{3 +}$
B $[Fe (H X_{2} O) X_{5} NO] X^{2 +}$
C $Fe X_{4} [Fe (CN) X_{6}] X_{3}$
D $[Fe (CN) X_{5} NO] X^{2 -}$

Answer: B

Nitrate is reduced to NO by

Fe X^{2 +}

in the presence of concentrated

H X_{2} SO X_{4}

. The NO then replaces one water ligand of

[Fe (H X_{2} O) X_{6}] X^{2 +}

to give the brown

[Fe (H X_{2} O) X_{5} NO] X^{2 +}

.

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