Ammonium molybdate reacts with phosphate in strongly acidic (nitric acid) solution according to $\mathrm{PO}{}_4{}^{3-}+12\mathrm{MoO}{}_4{}^{2-}+3\mathrm{NH}{}_4{}^{+}+24\mathrm{H}{}^{+}\to (\mathrm{NH}{}_4){}_3[\mathrm{P}(\mathrm{Mo}{}_3\mathrm{O}{}_{10}){}_4]+12\mathrm{H}{}_2\mathrm{O}$. Which of the following statements are correct? One or more options may be correct.

1. ATwelve molybdenum atoms combine with each phosphorus atom.
2. BThe oxidation state of Mo is $+6$ on both sides of the equation.
3. CThe reaction is a redox reaction in which Mo is reduced from $+6$ to $+5$.
4. DTwenty-four moles of $\mathrm{H}{}^{+}$ are consumed per mole of phosphate.