JEE Advanced levelOne or more correct optionsDifficulty 3 of 3pl104
PHBV contains two kinds of repeat units: −[O−CH(CHX3)−CHX2−CO]X− (HB, CX4HX6OX2) and −[O−CH(CX2HX5)−CHX2−CO]X− (HV, CX5HX8OX2). Which statements are correct (C 12, H 1, O 16)?
APHBV is formed by addition polymerisation of alkenes.
BThe HB unit has a molar mass of 86 g/mol.
CThe HV unit has a molar mass of 100 g/mol.
DA chain segment of 10 HB units and 5 HV units has a mass of 1360 g/mol (end groups neglected).
Answer: B, C, D
HB: 48+6+32=86; HV: 60+8+32=100; segment =10(86)+5(100)=860+500=1360. PHBV forms from hydroxy acids by condensation, so the addition-polymerisation statement is false.