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JEE Advanced levelSingle correct optionDifficulty 3 of 3pl091

Natural rubber (repeat unit , 68 g/mol, one per unit) adds bromine across its double bonds, . In a vulcanised sample, 4 percent of the isoprene units have lost their in forming sulfur links. Ignoring the mass of sulfur, 136 g of the polyisoprene part of this sample takes up how many moles of (assuming all remaining double bonds react)?

  1. A2.00 mol
  2. B0.08 mol
  3. C1.92 mol
  4. D1.96 mol

Answer: C

Units = 136/68 = 2.00 mol, of which 96 percent keep their double bond: 2.00 x 0.96 = 1.92 mol of , so 1.92 mol . 2.00 would ignore cross-linking.
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