JEE Advanced levelSingle correct optionDifficulty 3 of 3pl091
Natural rubber (repeat unit CX5HX8, 68 g/mol, one C=C per unit) adds bromine across its double bonds, C=C+BrX2CBr−CBr. In a vulcanised sample, 4 percent of the isoprene units have lost their C=C in forming sulfur links. Ignoring the mass of sulfur, 136 g of the polyisoprene part of this sample takes up how many moles of BrX2 (assuming all remaining double bonds react)?
A2.00 mol
B0.08 mol
C1.92 mol
D1.96 mol
Answer: C
Units = 136/68 = 2.00 mol, of which 96 percent keep their double bond: 2.00 x 0.96 = 1.92 mol of C=C, so 1.92 mol BrX2. 2.00 would ignore cross-linking.