The electron in Li^2+ is in the n=2 level. Take the ground-state ionisation energy of hydrogen as 13.6 eV and 1 eV per a

Question

The electron in Li^2+ is in the n=2 level. Take the ground-state ionisation energy of hydrogen as 13.6 eV and 1 eV per atom = 96.5 kJ mol^-1. Calculate the energy, in kJ mol^-1, needed to remove this electron from 1 mol of such ions. Give the answer to the nearest integer.

Accepted Answer

2953 kJ/mol

The electron in $Li X^{2 +}$ is in the $n = 2$ level. Take the ground-state ionisation energy of hydrogen as 13.6 eV and 1 eV per atom = $96.5 kJ mo l^{- 1}$ . Calculate the energy, in $kJ mo l^{- 1}$ , needed to remove this electron from 1 mol of such ions. Give the answer to the nearest integer.

Answer: 2953 kJ/mol

More questions on Ionisation enthalpy

The electron in LiX2+ is in the n=2 level. Take the ground-state ionisation energy of hydrogen as 13.6 eV and 1 eV per atom = 96.5 kJ mol−1. Calculate the energy, in kJ mol−1, needed to remove this electron from 1 mol of such ions. Give the answer to the nearest integer.

Answer: 2953 kJ/mol

More questions on Ionisation enthalpy

The electron in $Li X^{2 +}$ is in the $n = 2$ level. Take the ground-state ionisation energy of hydrogen as 13.6 eV and 1 eV per atom = $96.5 kJ mo l^{- 1}$ . Calculate the energy, in $kJ mo l^{- 1}$ , needed to remove this electron from 1 mol of such ions. Give the answer to the nearest integer.