JEE Advanced levelOne or more correct optionsDifficulty 3 of 3pt100
Use the following rule set. Slater's rules: write the configuration in groups (1s)(2s,2p)(3s,3p)(3d)(4s,4p)(4d)(4f)(5s,5p)… For an electron in an ns or np group, every other electron in the same group contributes 0.35 (0.30 for the 1s group), every electron in the (n−1) shell contributes 0.85, every electron in the (n−2) or lower shells contributes 1.00, and electrons in groups to the right contribute 0. For an electron in an nd or nf group, every other electron in the same group contributes 0.35, every electron in all groups to its left contributes 1.00, and groups to the right contribute 0. Z∗=Z−S. The 4s electrons of the 3d-series atoms Sc to Zn (configuration (3d)x(4s)2) are considered. Which statements are correct?
AZ∗(4s) of Sc is 3.00.
BZ∗(4s) of Mn is the same as that of Sc.
CZ∗(4s) rises by 0.15 for each 3d electron added.
DZ∗(4s) of Zn is 4.35.
Answer: A, C, D
Each extra 3d electron replaces a +1 nuclear proton gain by only 0.85 screening, so Z∗(4s) rises by 0.15 per element. Sc (x=1): 3.00; Mn (x=5): 3.60; Zn (x=10): 4.35. Mn differs from Sc.