JEE Main levelNumerical answerDifficulty 2 of 3pt074
Use the following rule set. Slater's rules: write the configuration in groups (1s)(2s,2p)(3s,3p)(3d)(4s,4p)(4d)(4f)(5s,5p)… For an electron in an ns or np group, every other electron in the same group contributes 0.35 (0.30 for the 1s group), every electron in the (n−1) shell contributes 0.85, every electron in the (n−2) or lower shells contributes 1.00, and electrons in groups to the right contribute 0. For an electron in an nd or nf group, every other electron in the same group contributes 0.35, every electron in all groups to its left contributes 1.00, and groups to the right contribute 0. Z∗=Z−S. Bromine (Z=35) is (1s)2(2s,2p)8(3s,3p)8(3d)10(4s,4p)7. Calculate the effective nuclear charge Z∗ on a 4p electron of bromine (answer to two decimal places).
Numerical answer type, tolerance 0.02.
Answer: 7.6
Same group: 6×0.35=2.10. The n=3 shell has 18 electrons: 18×0.85=15.30. Lower shells have 10 electrons: 10.00. S=27.40, so Z∗=35−27.40=7.60.