JEE Main levelSingle correct optionDifficulty 2 of 3pt068
Use the following rule set. Slater's rules: write the configuration in groups (1s)(2s,2p)(3s,3p)(3d)(4s,4p)(4d)(4f)(5s,5p)… For an electron in an ns or np group, every other electron in the same group contributes 0.35 (0.30 for the 1s group), every electron in the (n−1) shell contributes 0.85, every electron in the (n−2) or lower shells contributes 1.00, and electrons in groups to the right contribute 0. For an electron in an nd or nf group, every other electron in the same group contributes 0.35, every electron in all groups to its left contributes 1.00, and groups to the right contribute 0. Z∗=Z−S. The effective nuclear charge on the 4s electron of copper (Z=29; (1s)2(2s,2p)8(3s,3p)8(3d)10(4s)1) is:
A5.20
B3.70
C1.00
D3.35
Answer: B
No other electron is in the 4s group. The n=3 shell has 18 electrons: 18×0.85=15.30. The lower shells have 10 electrons: 10.00. S=25.30, so Z∗=29−25.30=3.70.