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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3pt053

Select the correct statement(s) about the position of elements in the long form table.

AThe element $[Xe] 4 f^{14} 5 d^{10} 6 s^{2} 6 p^{5}$ is in group 17, period 6.
BThe element $[Ar] 3 d^{10} 4 s^{1}$ is in group 1 because it has one electron in the outer s orbital.
CThe element $[Ar] 3 d^{5} 4 s^{1}$ is in group 6.
DThe element $[Rn] 5 f^{14} 6 d^{2} 7 s^{2}$ is in group 4, period 7.

Answer: A, C, D

A: the 6p5 outer configuration gives group

10 + 2 + 5 = 17

in period 6. B is false because for d-block elements both ns and (n-1)d electrons count, so group

= 10 + 1 = 11

(copper). C:

5 + 1 = 6

. D:

2 + 2 = 4

in period 7.

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