Match the valence configuration (List I) with the type of element (List II). List I: P. $[Xe] 4 f^{3} 6 s^{2}$ ; Q. $[Ar] 3 d^{2} 4 s^{2}$ ; R. $[Ne] 3 s^{2} 3 p^{5}$ ; S. $[Ar] 4 s^{2}$ . List II: 1. alkaline earth metal; 2. group 4 d-block metal; 3. lanthanoid; 4. halogen.

AP-3, Q-2, R-4, S-1
BP-3, Q-4, R-2, S-1
CP-1, Q-2, R-4, S-3
DP-2, Q-3, R-1, S-4

Answer: A

P has the last electrons in 4f, so it is a lanthanoid (3). Q has 3d2 4s2 with four valence electrons, so group 4 (2). R is 3s2 3p5, group 17, a halogen (4). S is 4s2, group 2, an alkaline earth metal (1).

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Match the valence configuration (List I) with the type of element (List II). List I: P. [Xe]4f36s2; Q. [Ar]3d24s2; R. [Ne]3s23p5; S. [Ar]4s2. List II: 1. alkaline earth metal; 2. group 4 d-block metal; 3. lanthanoid; 4. halogen.

Answer: A

More questions on Modern periodic table and classification of elements

Match the valence configuration (List I) with the type of element (List II). List I: P. $[Xe] 4 f^{3} 6 s^{2}$ ; Q. $[Ar] 3 d^{2} 4 s^{2}$ ; R. $[Ne] 3 s^{2} 3 p^{5}$ ; S. $[Ar] 4 s^{2}$ . List II: 1. alkaline earth metal; 2. group 4 d-block metal; 3. lanthanoid; 4. halogen.