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JEE Advanced levelSingle correct optionDifficulty 3 of 3pt009

A, B and C are consecutive members of group 14 of the long form of the periodic table, with A in period 3. The sum of the atomic numbers of A, B and C is

A76
B110
C66
D96

Answer: D

A is silicon (Z = 14). Period 4 has 18 elements, so B has

Z = 14 + 18 = 32

, and C in period 5 has

Z = 32 + 18 = 50

. The sum is

14 + 32 + 50 = 96

.

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