JEE Main levelNumerical answerDifficulty 2 of 3pt001
An element has atomic number 33. Another element lies in the same group of the long form of the periodic table but in period 6. Find the atomic number of this element (nearest integer).
Numerical answer type, tolerance 0.5.
Answer: 83
Atomic number 33 is arsenic, group 15, period 4. Moving down the group, period 5 has 18 elements and period 6 has 32, so the atomic number is 33+18+32=83 (bismuth).