JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ph186
Given E∘ (V): ClX2/ClX−=1.36, BrX2/BrX−=1.09, IX2/IX−=0.54, FeX3+/FeX2+=0.77, MnOX4X−/MnX2+ (acidic) =1.51. Under standard conditions, which statement(s) is/are correct?
AFeX3+ can oxidise IX− to IX2
BFeX3+ can oxidise BrX− to BrX2
CAcidified MnOX4X− can oxidise ClX− to ClX2
DBrX2 can oxidise ClX− to ClX2
Answer: A, C
Ecell∘ must be positive. FeX3++IX−: 0.77−0.54=+0.23V (spontaneous). FeX3++BrX−: 0.77−1.09=−0.32V. MnOX4X−+ClX−: 1.51−1.36=+0.15V. BrX2+ClX−: 1.09−1.36=−0.27V. Options 1 and 3 are correct.