Counting each Xe=O as one sigma and one pi bond, the sum of the total number of Xe=O pi bonds and the total number of lone pairs on Xe, taken over the three molecules XeOF4, XeO2F2 and XeO3F2, is

JEE Advanced levelSingle correct optionDifficulty 3 of 3ph155

Counting each Xe=O as one $σ$ and one $π$ bond, the sum of the total number of Xe=O $π$ bonds and the total number of lone pairs on Xe, taken over the three molecules $XeOF X_{4}$ , $XeO X_{2} F X_{2}$ and $XeO X_{3} F X_{2}$ , is

π

bonds: 1 in

XeOF X_{4}

, 2 in

XeO X_{2} F X_{2}

, 3 in

XeO X_{3} F X_{2}

, total 6. Lone pairs on Xe: 1 (

XeOF X_{4}

), 1 (

XeO X_{2} F X_{2}

), 0 (

XeO X_{3} F X_{2}

), total 2. Sum =

6 + 2 = 8