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JEE Advanced levelSingle correct optionDifficulty 3 of 3ph072

One mole of $Br X_{2}$ is completely converted into the highest bromine fluoride by excess $F X_{2}$ , and that product is then completely hydrolysed to $HBrO X_{3}$ and $HF$ . The number of moles of $HF$ formed is

A5
B2
C10
D15

Answer: C

Br X_{2} + 5 F X_{2} 2 BrF X_{5}

gives 2 mol of

BrF X_{5}

. Each mole reacts as

BrF X_{5} + 3 H X_{2} O HBrO X_{3} + 5 HF

and gives 5 mol HF, so the total is

2 \times 5 = 10

mol.

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