JEE Main levelSingle correct optionDifficulty 2 of 3ph027
Using Lewis structures in which chlorine forms Cl=O double bonds (no charge separation), the total number of Cl=O bonds present in the four molecules HOCl, HClOX2, HClOX3 and HClOX4 together is
A10
B4
C8
D6
Answer: D
Cl=O bonds: HOCl has 0, HClOX2 has 1, HClOX3 has 2 and HClOX4 has 3. The total is 0 + 1 + 2 + 3 = 6.