Numerical answer type, answer in %, tolerance 0.01.
Answer: 13.74 %
Moles thiosulphate = 0.500×0.0384=0.0192; moles IX2=0.0096 = moles OX3. Total gas = 2.24/22.4=0.100 mol, so OX2 = 0.0904 mol. Mass of OX3 = 0.0096×48=0.4608 g and of OX2 = 0.0904×32=2.8928 g. Mass percent of OX3 = 0.4608/3.3536×100=13.74.