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NEET levelSingle correct optionDifficulty 1 of 3pn021

The brown ring formed at the junction of the layers in the brown ring test for nitrate is due to the complex

A $[Fe (H X_{2} O) X_{5} (NO X_{2})] X^{2 +}$
B $[Fe (H X_{2} O) X_{5} (NO)] X^{2 +}$
C $[Fe (H X_{2} O) X_{6}] X^{2 +}$
D $[Fe (CN) X_{5} (NO)] X^{2 -}$

Answer: B

Nitrate is reduced to

NO

by

Fe X^{2 +}

in presence of conc.

H X_{2} SO X_{4}

;

NO

then replaces one water in the iron(II) aqua ion to give the brown

[Fe (H X_{2} O) X_{5} (NO)] X^{2 +}

. The nitroprusside ion is a different complex.

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