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JEE Main levelSingle correct optionDifficulty 2 of 3pn009

The correct order of boiling points of the hydrides of group 16 is

A $H X_{2} O > H X_{2} S > H X_{2} Se > H X_{2} Te$
B $H X_{2} Te > H X_{2} Se > H X_{2} S > H X_{2} O$
C $H X_{2} O > H X_{2} Te > H X_{2} Se > H X_{2} S$
D $H X_{2} O > H X_{2} Se > H X_{2} Te > H X_{2} S$

Answer: C

Boiling points of

H X_{2} S

,

H X_{2} Se

and

H X_{2} Te

rise with molar mass (stronger van der Waals forces):

H X_{2} S < H X_{2} Se < H X_{2} Te

.

H X_{2} O

is far higher because of extensive hydrogen bonding. The order is therefore

H X_{2} O > H X_{2} Te > H X_{2} Se > H X_{2} S

.

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