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JEE Main levelOne or more correct optionsDifficulty 2 of 3pb211

Select the correct statement(s) about tin chlorides.

A $SnCl X_{2}$ dissolves in excess NaOH to give a soluble stannite.
B $SnCl X_{2}$ is a reducing agent.
C $SnCl X_{4}$ is a good reducing agent in acid solution because tin is already in a high oxidation state.
D $SnCl X_{2}$ undergoes hydrolysis in water to give a basic chloride such as $Sn (OH) Cl$ .

Answer: A, B, D

Sn(II) readily goes to Sn(IV), so

SnCl X_{2}

reduces. It hydrolyses partly:

SnCl X_{2} + H X_{2} O Sn (OH) Cl + HCl

.

Sn (OH) X_{2}

is amphoteric and dissolves in excess alkali.

SnCl X_{4}

is already in the stable +4 state and cannot be oxidised further, so it is not a reductant.

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