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JEE Advanced levelSingle correct optionDifficulty 3 of 3pb195

10.0 g of is heated strongly (). All the is passed over excess red hot carbon () and the CO formed reduces excess (). Using C = 12, O = 16, Ca = 40, Fe = 56 and 100 % yield in every step (no recycling of the new ), the mass of iron formed is

  1. A7.47 g
  2. B16.80 g
  3. C3.73 g
  4. D11.20 g

Answer: A

Molar mass of = 100 g/mol, so = 0.10 mol. Each gives 2 CO, so CO = 0.20 mol. Three CO give 2 Fe, so Fe = 0.20 x 2/3 = 0.1333 mol. Mass = 0.1333 x 56 = 7.47 g.
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