Numerical answer type, answer in g, tolerance 0.01.
Answer: 1.91 g
Molar mass of NaHCOX3 = 23 + 1 + 12 + 48 = 84 g/mol, so 7.30 g is 0.08690 mol. Two moles of NaHCOX3 give one mole of COX2, so n(COX2) = 0.043452 mol. Mass = 0.043452 x 44 = 1.9119 g, i.e. 1.91 g.