Answer: D
The compound is trans-1-bromo-2-methylcyclohexane. The diequatorial chair has no anti-periplanar hydrogen, so the ring flips to the diaxial chair, where the methyl group is axial and the C-2 hydrogen is equatorial. Only the axial hydrogen on C-6 is anti to bromine, so elimination gives the less substituted 3-methylcyclohexene instead of the Saytzeff alkene.