The halide shown undergoes E2 elimination with sodium ethoxide. Counting E and Z isomers as different compounds and ignoring any rearrangement or optical isomerism, how many distinct alkenes can be formed?

Answer: B

The compound is 2-bromo-4-methylpentane. Removal of a hydrogen from C-1 gives 4-methylpent-1-ene, and removal from C-3 gives (E)- and (Z)-4-methylpent-2-ene. The other side of the molecule offers no further beta-hydrogens, so the total is 1 + 2 = 3.

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