How many beta-hydrogens does the halide shown possess (hydrogens on carbons directly attached to the carbon bearing the halogen)?

Answer: C

The compound is 2-bromo-3-methylbutane. The carbon bearing bromine is attached to a methyl group (3 H) and to the CH(CH3)2 carbon (1 H). The beta-hydrogens therefore total 3 + 1 = 4.

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