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NEET levelSingle correct optionDifficulty 1 of 3o4176

1,2-Dibromoethane is treated with excess $NaNH X_{2}$ and then with water. The final product is:

Aethene
Bethane
Cethyne
Dethanol

Answer: C

A vicinal dihalide loses two molecules of HX with a strong base to give an alkyne.

BrCH X_{2} CH X_{2} Br CH X_{2} = CHBr HC \equiv CH

(as the sodium acetylide, protonated on adding water).

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