Ethanol (4.6 g, $M = 46$ ) is converted completely (a) into diethyl ether ( $M = 74$ ) by conc. $H X_{2} SO X_{4}$ at 413 K with excess alcohol (an SN2 path), and (b) into ethene ( $M = 28$ ) by conc. $H X_{2} SO X_{4}$ at 443 K (an E2-like path). The ratio of mass of ether in (a) to mass of ethene in (b) is closest to

Answer: B

4.6 g ethanol is

4.6/46 = 0.100

mol. Two moles of ethanol give one mole of ether, so the mass of ether is

0.050 \times 74 = 3.70

g. One mole of ethanol gives one mole of ethene, so the mass of ethene is

0.100 \times 28 = 2.80

g. The ratio is

3.70/2.80 = 1.32