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JEE Main levelSingle correct optionDifficulty 2 of 3o4156

Neopentyl bromide, $(CH X_{3}) X_{3} C - CH X_{2} Br$ , is treated with $NaOEt$ in ethanol. Which statement is correct?

A2-methylbut-2-ene is formed in an E2 step
B2,2-dimethylpropene is formed rapidly
CNo alkene is formed by E2 because there is no beta-hydrogen, and SN2 is extremely slow
DRapid SN2 gives neopentyl ethyl ether

Answer: C

The beta carbon is the quaternary

C (CH X_{3}) X_{3}

, so there is no beta-hydrogen for E2. SN2 at the primary carbon is blocked by the neighbouring tert-butyl group, so substitution is extremely slow.

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