Answer: A, B, C
The secondary cation CHX3−CHX+−C(CHX3)X3 undergoes a methyl shift to the tertiary cation (CHX3)X2CX+−CH(CHX3)X2. Loss of the tertiary H gives the tetrasubstituted 2,3-dimethylbut-2-ene (major), and loss of a methyl H gives 2,3-dimethylbut-1-ene (minor). The unrearranged alkene is not the major product.