Numerical answer type, tolerance 0.5.
Answer: 5
Beta-hydrogens are on three different carbons. Loss from the ethyl CHX3 gives 3-methylhex-2-ene (E and Z, 2). Loss from the methyl group gives 2-ethylpent-1-ene (1). Loss from the propyl CHX2 next to the cation carbon gives 3-methylhex-3-ene (E and Z, 2). Total 2+1+2=5.