meso-1,2-Dibromo-1,2-diphenylethane and its racemic diastereomer (1R,2R / 1S,2S) are each treated with one equivalent of $\mathrm{NaOEt}$ (anti E2 giving 1-bromo-1,2-diphenylethene). Select all correct statements.

1. AThe meso isomer gives (E)-1-bromo-1,2-diphenylethene, in which the two phenyl groups are cis.
2. BThe racemic (1R,2R / 1S,2S) isomer gives (Z)-1-bromo-1,2-diphenylethene, in which the two phenyl groups are trans.
3. CThe meso isomer gives (Z)-1-bromo-1,2-diphenylethene.
4. DBoth diastereomers give the same alkene because the benzylic hydrogens are acidic and the geometry is scrambled.