2-Bromobutane on heating with alcoholic $KOH$ gives mainly

Abut-1-ene
Bbutan-2-ol
Cbut-2-ene
Dbut-1-yne

Answer: C

E2 elimination from a secondary halide with a small base follows the Saytzeff rule: the more substituted alkene predominates. Loss of H from C-3 gives the disubstituted but-2-ene, which is more stable than but-1-ene.

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2-Bromobutane on heating with alcoholic KOH gives mainly

Answer: C

More questions on E2 mechanism and anti-periplanar requirement

2-Bromobutane on heating with alcoholic $KOH$ gives mainly