Answer: A
The tertiary cation CHX3CHX2−CX+(CHX3)−CHX2CHX3 is formed; no shift can improve it. Loss of H from a CH2 gives the trisubstituted 3-methylpent-2-ene; loss from the methyl gives disubstituted 2-ethylbut-1-ene (minor). Between E and Z isomers of 3-methylpent-2-ene the E isomer is more stable, since the two larger groups avoid each other.