Answer: A, B, C
The alkane is 2,2-dimethylbutane. Weights: nine CHX3 H on the tert-butyl group give 9; the two CHX2 H give 7.6; the terminal CHX3 gives 3; total 19.6 (45.9%, 38.8%, 15.3%). The secondary chloride, 2-chloro-3,3-dimethylbutane, has four different groups on the CHCl carbon. The molecule has no tertiary hydrogen, so D is false.