The alkene shown reacts with $\mathrm{HBr}$ (no peroxide). Select all correct statements.

The alkene is 3-methylpent-1-ene. Protonation of C-1 gives a secondary cation at C-2; a hydride shift from C-3 gives the tertiary cation, and bromide gives 3-bromo-3-methylpentane. This product has two identical ethyl groups on the carbon bearing Br, so it has no stereocentre and statement D is false.