The major product of propene on treatment with BH3.THF followed by H2O2/NaOH is

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The major product of propene on treatment with $BH X_{3} \cdot THF$ followed by $H X_{2} O X_{2} / NaOH$ is

Apropane-1,2-diol
Bpropan-2-ol
Cpropan-1-ol
Dpropanal

Answer: C

Hydroboration-oxidation gives the anti-Markovnikov alcohol because boron adds to the less substituted carbon. Boron is later replaced by OH. Propene therefore gives

CH X_{3} CH X_{2} CH X_{2} OH

, propan-1-ol.

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The major product of propene on treatment with BHX3​⋅THF followed by HX2​OX2​/NaOH is

Answer: C

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The major product of propene on treatment with $BH X_{3} \cdot THF$ followed by $H X_{2} O X_{2} / NaOH$ is