Answer: A, B, D
With peroxide, Br⋅ adds to C-1 to give the secondary radical at C-2 and then 1-bromo-3-methylbutane forms; radicals do not undergo 1,2-hydride shifts under these conditions. In the dark, the secondary cation rearranges by a hydride shift to the tertiary cation, giving 2-bromo-2-methylbutane. So C is false.