JEE Advanced levelSingle correct optionDifficulty 3 of 3o2103
Using the bond dissociation energies H−Cl=431, H−Br=366 and secondary C-H =410kJmol−1, the enthalpy changes (kJ/mol) of the step R⋅+HXR−H+X⋅ (R = secondary alkyl) for X = Cl and X = Br respectively are
A+21 and -44
B-21 and -44
C-21 and +44
D+21 and +44
Answer: A
ΔH=D(H−X)−D(R−H). For Cl: 431−410=+21. For Br: 366−410=−44. Thus the chain-transfer step is endothermic for HCl (chain does not propagate) and exothermic for HBr (peroxide effect operates).