2-Methylbutane is monochlorinated with $Cl X_{2}$ and light. How many monochloro products are possible in total, counting all stereoisomers (enantiomers) as separate compounds?

Answer: D

Four constitutional isomers form. 1-chloro-2-methylbutane (stereocentre C-2) and 2-chloro-3-methylbutane (stereocentre C-2) are chiral and each exists as a pair of enantiomers. 2-chloro-2-methylbutane and 1-chloro-3-methylbutane are achiral. Total

= 2 + 2 + 1 + 1 = 6

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2-Methylbutane is monochlorinated with ClX2​ and light. How many monochloro products are possible in total, counting all stereoisomers (enantiomers) as separate compounds?

Answer: D

More questions on Free radical substitution of alkanes and selectivity

2-Methylbutane is monochlorinated with $Cl X_{2}$ and light. How many monochloro products are possible in total, counting all stereoisomers (enantiomers) as separate compounds?